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8.1Acids,
Bases and
Amphoteric
Substances
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8.1.1-Define acids, bases and amphoteric
compounds;
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Theory
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Acid
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Base
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Arrhenius
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generates [H+]
in solution
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generates [OH-]
in solution
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Example
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NaOH Na+ + OH-
HCl Cl- + H+
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Bronsted-Lowery
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anything that
donates a [H+] (proton donor)
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anything that
accepts a [H+] (proton acceptor
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Example
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HNO2 + H2O →
NO2- + H3O+
(Porton donor) (Proton acceptor )
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Lewis
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accepts an electron
pair
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donates an electron pair
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Example
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Cl- + FeCl3→[FeCl4]-
(Base) (Acid)
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NH3 + H+ → NH4+
(Base) (Acid)
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8.1.2-explain the significance of acid base reactions in daily
life
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1- Food preservation
Acid
such as vinegar ,lemon lime juice will preserved food because the pH is to
high bacteria to serviced
2- Allergic Reaction
Acid solution prevent all allergic reaction HCl and NH4Cl
used in cough syrups.
Aunt biting transfer Formic acid (HCOOH) which inching in the body
3- Gastric acidity
when a heart
burn is experienced , actually concentration of HCl is sensation of burning
When this people often Anta acid which contain base
such as Al(OH)3 and Mg (OH)2
The stomach acid
react with anat acid to
produce a salt and water
4-Curdling of
milk:
Milk
is comprised of several compounds, primarily fat, protein, and sugar. The
protein in milk is normally suspended in a colloidal solution, which means
that the small protein molecules float around freely and independently. These
floating protein molecules refract light and give milk its white appearance.
Normally
these protein molecules repel each other, allowing them to float about
without clumping, but when the pH of their solution changes, they can
suddenly attract one another and form clumps. This is exactly what happens
when milk curdles. As the pH drops and becomes more acidic, the protein
(casein) molecules attract one another and become "curdles"
floating in a solution of translucent whey.
This
clumping reaction happens more swiftly at warmer temperatures than it does at
cold temperatures.
5-Improtantce of Iodine in salt
Human body need iodine for thyroid to produce
couple of essential hormones - thyroxie
and tri iodothgronie The deficiency
of iodine the decrease the intelligence (IQ) of person. it use full to remove
toxic element such as bromine (Br) ,fluorine ( F) and Lead(Pb) , Mercury(Hg)
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8.1.3- Calculate molarity, molality
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8.2
Lowry - Bronsted
Concept of Acids and Bases
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8.2.1-Define acids and bases according to
Lowry – Bronsted theory;
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In chemistry, the Brønsted-Lowry theory is an
acid-base theory, proposed independently by Johannes Nicolaus Brønsted and
Thomas Martin Lowry in 1923. In this system, Brønsted-Lowry acids and
Brønsted-Lowry bases are defined as follows:
an acid is a molecule or ion that is able
to lose, or "donate," a hydrogen cation (H+, a proton); a base is a species with the ability
to gain, or "accept," a hydrogen cation (a proton).
It
follows that, if a compound is to behave as an acid by donating a proton,
there must be a base to accept the proton. So the Brønsted-Lowry concept can
be defined by the reaction:
Acid + Base Conjugate base + Conjugate
acid
The
conjugate base is the ion or molecule remaining after the acid has lost a
proton, and the conjugate acid is the species created when the base accepts
the proton. The reaction can proceed in either the forward or backward
direction; in each case, the acid donates a proton to the base.
Brønsted-Lowry
acid-base theory has several advantages over Arrhenius theory. Consider the
following reactions of acetic acid (CH3COOH), the
organic acid that gives vinegar its characteristic taste:
- CH3COOH + H2O ó H3O+ + CH3COO-
- CH3COOH + NH3 ó NH4+ + CH3COO-
Both
theories easily describe the first reaction: CH3COOH acts as an
Arrhenius acid because it acts as a source of H3O+ when dissolved in water, and it acts as a
Brønsted acid by donating a
proton to water.
In the second example CH3COOH undergoes the same transformation, in this
case donating a proton to ammonia (NH3), but this
cannot be described using the Arrhenius definition of an acid because the
reaction does not produce hydronium.
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8.3
Conjugate Acids and Bases
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8.3.1-Define conjugate acid and conjugate
base;
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Conjugate acid:
A
strong acid ionizes completely in an aqueous solution by losing one proton, according
to the following equation:
HA (aq)
H+ (aq) + A−
(aq)
where
HA is a protonated acid, H+ is the free acidic proton, and A-
is the conjugate base.
Conjugate base of weak acid are strong for example
CH3COOH ó H+ + CH3COO-
The CH3COO- ion
is strong Conjugate base
Conjugate base :
A
strong base ionizes completely in an
aqueous solution by accepting one
proton, according to the following equation:
BOH (aq)
B+ (aq) + OH−
(aq)
where
BOH is generate OH- is the free OH-, and B+ is the conjugate acid .
Conjugate acid of weak base are strong for example
NH4
OH ó NH4+ + OH-
The NH4+ ion is strong
Conjugate acid
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8.3.2 -Compare the strength of conjugate
acids and bases;
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Strong acids yield weak conjugate bases.
Strong acids completely dissociate
into free protons and their conjugate base in
water.
HCl ó H+ + Cl-
The Cl- is weak
conjugate base
Conjugate base of weak acid are strong for example
CH3COOH ó H+ + CH3COO-
The CH3COO- ion
is strong
Strong bases yield weak conjugate acid.
Strong base completely dissociate
into free OH- and their conjugate acid in water.
NaOH ó Na+ + OH-
Conjugate acid of weak base are strong for example
NH4
OH ó NH4+ + OH-
The NH4+ ion is strong
Conjugate acid
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8.4
Strengths of Acids and
Bases
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8.4.1-Explain the ionization constant of
water (Kw);
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H2O
ó H+ + OH-
According to
equilibrium constant l
The concentration
of water in water is 55.55 mol/dm3
The
equilibrium constant is 1.x10 -16
Kw =1x 10-14 =[ H+][OH-]
OR
1x 10-14
=[ H+][OH-]
As we know
that when water dissociate it from
equal H+ and OH- ions , [H+] = [OH-]
Suppose the
concentration of H+ and OH- ion is
X mol/dm3
1x 10-14
= X .
X
1x 10-14
= X2
Taking square
root on both side
X= 1x 10-7
[H+]=1x
10-7
[OH-]
= 1x 10-7
Therefore the
pH and pOH is 7
According to
dissociation of water
Kw =1x 10-14
1x 10-14
=[ H+][OH-]
Apply log on
both side
log 1x 10-14
= log [ H+] + log [OH-]
Multiple by
(-) on both side
-log 1x 10-14 ={ -log [ H+] }+{
-log [OH-]}
As we know
that
pH = - log [
H+] , pOH = -log [OH-] and
-log 1x10-14=14
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8.4.2-compare the strength of acids and
bases using pH and pOH;
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Acidic Strength increase
Acidic Strength decrease
[H+]
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100
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10-1
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10-2
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10-3
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10-4
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10-5
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10-6
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10-7
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10-8
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10-9
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10-10
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10-11
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10-12
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10-13
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10-14
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pH
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0
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1
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2
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3
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4
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5
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6
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7
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8
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9
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10
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11
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12
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13
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14
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[OH-]
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10-14
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10-13
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10-12
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10-11
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10-10
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10-9
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10-8
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10-7
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10-6
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10-5
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10-4
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10-3
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10-2
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10-1
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10-14
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pOH
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14
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13
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12
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11
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10
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9
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8
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7
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6
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5
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4
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3
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2
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1
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0
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Basic strength decrease Basic
strength increase
Decrease the concentration of OH- will increase the pOH of solution,
Decrease
the concentration of H+ will increase the pH of solution,
Increase the concentration of OH- will decrease the pOH of solution,
Increase the concentration of H+- will increase the pH of solution
Acidic Strength increase
Ka
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100
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10-1
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10-2
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10-3
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10-4
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10-5
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10-6
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10-7
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10-8
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10-9
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10-10
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10-11
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10-12
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10-13
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10-14
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pKa
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0
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1
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2
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3
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4
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5
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6
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7
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8
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9
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10
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11
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12
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13
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14
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Kb
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10-14
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10-13
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10-12
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10-11
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10-10
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10-9
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10-8
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10-7
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10-6
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10-5
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10-4
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10-3
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10-2
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10-1
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10-14
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pKb
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14
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13
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12
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11
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10
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9
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8
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7
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6
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5
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4
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3
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2
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1
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0
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Basic strength increase
To calculate a pH value, it is
easiest to follow the standard "Start, Change, Equilibrium"
process.
Example Problem: Determine the
pH of a 0.25 M solution of HBr.
Answer:
HBr H+ + Br -
Initial 0.25M Nil Nil
Equilibrium (0.25M -0.25 M) +0.25M +0.25M
pH = -log [H+]
=
-log (0.25)
= 0.60
http://www.uiowa.edu/~chemrev/chem-basic/acid_base.htm
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8.4.3- Derive the dissociation constants of acid, base and water
(Ka, Kb and Kw);
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Dissociation of Acid
CH3COOH + H2O ó H3O+ + CH3COO-
Dissociation of Base
NH3 + H2O ó NH4+ +OH-
Show
That Kw =Ka x Kb
CH3COOH + H2O ó H3O+ + CH3COO-
CH3COO- + H2O ó CH3COOH + OH-
K a
x K b = x
Ka
x Kb= [H3O+][OH-]
According
to dissociation constant of water
Kw
= [H3O+][OH-]
Since
Kw = Ka x Kb
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8.4.4- Calculate the H O3+ concentration by using the given Ka and
molar
concentration of weak acid;
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Example
Problem: Determine the pH of .30 M acetic acid ( (CH3COOH) with the Ka of 1.8x10-5.
Answer :
Write the
equilibrium equation for the acid
CH3COOH + H2O ó H3O+ + CH3COO-
Write the
equilibrium expression and the Ka value :
Ka =1.8x10-5
CH3COOH
+ H2O ó H3O+ + CH3COO-
At initial
time 0.30M Nil Nil
At
Equilibrium 0.30-x x x
Substitute the
variable (disregard the “-x” because
it is so small compared to the 0.30 and solve for [H+]
Ka =1.8x10-5
= x.x ÷ (0.30 –x)
1.8 x10-5= x2 ÷ (0.30 –x)
x = 2.3x10-3
pH = - log [H+]
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8.4.5- Explain the term ‘leveling effect’;
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8.5
Lewis Concept of Acids
and Bases
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8.5.1-Define Lewis acids and bases along
with examples;
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In 1923 G. N. Lewis suggested another way of looking at
the reaction between H + and
OH - ions. In the Bronsted
model, the OH - ion
is the active species in this reaction it
accepts an H + ion to
form a covalent bond. In the Lewis model, the H + ion is the active species it accepts a pair of electrons from the OH - ion to form a covalent bond.
In the Lewis theory of acid-base reactions, bases donate
pairs of electrons and acids accept pairs of electrons.
A Lewis acid is therefore any substance, such as
the H+ ion, that can
accept a pair of nonbonding electrons.
In other words, a Lewis acid is an electron-pair acceptor.
A Lewis baseis any substance,
such as the OH- ion,
that can donate a pair of nonbonding electrons.
A Lewis base is
therefore an electron-pair donor.
The Lewis theory suggests that acids
react with bases to share a pair of electrons, with no change in the
oxidation numbers of any atoms. Many chemical reactions can be sorted into
one or the other of these classes. Either electrons are transferred from one
atom to another, or the atoms come together to share a pair of electrons.
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8.5.2-Classify the given compounds
(e.g. NH3, AlCl3, BF3, etc.) as Lewis acids or bases;
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