S.No
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Question
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Consider two metals A and B , each having a mass of
100 g and initial temperature of 20 0C.The specific heat of A is larger than
that B .Under the same heating conditions ,
which metal would take longer to reach a temperature of 21 0C
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A quantity of 2.00 x102 ml of 0.862M HCl is mixed with 2.00 x 102 ml of 0.431M Ba(OH)2 in a
constant- pressure Calorimeter that
has a heat capacity is 453J/0C .The initial temperature of HCl and Ba(OH)2 solution is the same at 20.48 0C, the of
neutralization is -56.2 kJ. What is the final temperature of the solution.
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From the following heats of
combustion
CH3OH (l)
+ 3/2 O2g) → CO2
(g)
∆H=-726kJ
C (graphite) + O2(g)
→ CO2 (s)
∆H=-393kJ
H2(g) + ½ O2(g) → H2O (l) ∆H=-285.8kJ
Calculate the enthalpy of
formation of methanol (CH3OH)
C (graphite) + ½
O2(g) +2 H2(g)
→CH3OH(l)
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From the following heats of
combustion
C2H2 (g)
+ 7 O2g) →4 CO2 (g) + 6H2O(l)
∆H=-3119.6kJ
C (graphite) + O2(g)
→ CO2 (s)
∆H=-393kJ
H2(g) + ½ O2(g) → H2O (l) ∆H=-285.8kJ
Calculate the enthalpy of
formation of C2H2 (g)
2C (graphite) + 2 H2(g)
→C2H2 (g)
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Find
the heat of formation of Acetic acid at 25C
2C
+ 2H2 +O2 → CH3COOH
∆H= ?
(a)
C + O2 →
CO2 ∆H=-394 kJl
(b)
H2 + ½
O2 → H2O ∆H=-286 kJ
(c)
CH3COOH + 2O2 → 2CO2 + 2H2O ∆H=-870.8 kJ
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Explain Born –Haber cycle by using the enthalpy changes of the
following reactions
Na(s) →Na(g)
∆H=109 j/mol , Na(g) →Na+(g)
∆H= 494 j/mol
Cl2(g )→ 2Cl(g)
∆H=242 j/mol, Cl (g) →Cl-(g) ∆H= -363 j/mol
and Na(s)+ ½ Cl2 (g)→ NaCl (s)
∆H= -471 j/mol
Calculate the enthalpy
change of Na+(g)
+Cl-(g) →NaCl (s)
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My objective is "To make chemistry is a simple subject for learners and undergraduate student globally and Specially my country "Pakistan"
Friday, 3 August 2012
11. ERQs of Thermochemistry
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