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17.4 Notes
ALCOHOL
Alcohols are hydroxy-substituted
alkanes, alkenes, or alkynes in which the substitution occurs on a saturated
carbon.
The general formula for alcohols is
R—OH, where the R group can represent the alkyl, alkenyl, or alkynal groups. In
the case of substitution on alkenes and alkynes, only saturated carbons may be
substituted. For example, the following compounds are all alcohols:
If the hydroxyl group were
substituted for a hydrogen on an unsaturated carbon, an alcohol would not form.
For example, substituting the hydroxyl group for a terminal hydrogen of
1-propene gives an unstable enol that tautomerizes to a ketone.
You can use both the common and IUPAC systems to name
alcohols. In the common system, you name an alcohol by listing the alkyl group
and adding the word alcohol. Following are some examples of alcohols and
their common names:
In the IUPAC system, use the following series of rules to
name alcohols:
- Pick out the longest continuous chain to which the hydroxyl group is directly attached. The parent name of the alcohol comes from the alkane name for the same chain length. Drop the -e ending and add -ol.
- Number the parent chain so that the carbon bearing the hydroxyl group has the lowest possible number. Place the number in front of the parent name.
- Locate and name substituents other than the hydroxyl group.
The following examples show how you apply these rules:
You may classify alcohols as primary (1°), secondary (2°),
or tertiary (3°), based on the class of carbon to which the hydroxyl group
(—OH) is directly bonded. For example, 1-propanol is a 1° alcohol, 2-propanol
is a 2° alcohol, and 2-methyl-2-propanol is a 3° alcohol.
Alcohols contain both a polar —OH group and a nonpolar alkyl
group. As a result of this composition, alcohols that have small alkyl chains
tend to be water soluble. As alkyl chain length increases, water solubility
decreases.
Through the OH group, alcohols are capable of forming
hydrogen bonds to themselves, other alcohols, neutral molecules, and anions.
This bond formation leads to abnormally high boiling points compared to other
organic molecules of similar carbon chain length.
Reference:
Oxidative Cleavage of Diols
Reaction type: Oxidation-reduction
Summary
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Questions:
Can you recall a reaction that forms carbonyl groups via cleavage of an alkene ?
How are 1,2-diols made from alkenes ?
What are the oxidation states of the iodine in HIO4 and HIO3 ?
Can you recall a reaction that forms carbonyl groups via cleavage of an alkene ?
How are 1,2-diols made from alkenes ?
What are the oxidation states of the iodine in HIO4 and HIO3 ?
PERIODATE
CLEAVAGE OF 1,2-DIOLS
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The mechanism is not trivial, so
attention here is focused on the actual cleavage step. Prior to this, the
alcohol reacts to form a cyclic periodate ester (shown). The periodate
ester undergoes are arrangement of the electrons, cleaving the C-C
bond, and forming two C=O.
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Reference:
Esters are compounds that are commonly formed by the
reaction of oxygen-containing acids with alcohols. The ester functional group
is the
Alcohols can be converted to esters by means of the Fischer
Esterification Process. In this method, an alcohol is reacted with a carboxylic
acid in the presence of an inorganic acid catalyst.
Because the reaction is an equilibrium reaction, in order to
receive a good yield, one of the products must be removed as it forms. Doing
this drives the equilibrium to the product side.
In this process, benzene sulfonic acid is reacted with
aqueous sodium hydroxide. The resulting salt is mixed with solid sodium
hydroxide and fused at a high temperature. The product of this reaction is
sodium phenoxide, which is acidified with aqueous acid to yield phenol.
In the Dow process, chlorobenzene is reacted with dilute
sodium hydroxide at 300°C and 3000 psi pressure. The following figure
illustrates the Dow process.
The air oxidation of cumene (isopropyl benzene) leads to the
production of both phenol and acetone, as shown in the following figure. The
mechanisms for the formation and degradation of cumene hydroperoxide require
closer looks, which are provided following the figure.
Cumene hydroperoxide formation.
The formation of the hydroperoxide proceeds by a free radical chain reaction. A
radical initiator abstracts a hydrogen-free radical from the molecule, creating
a tertiary free radical. The creation of the tertiary free radical is the
initial step in the reaction.
In the next step, the free radical is attracted to an oxygen
molecule. This attraction produces the hydroperoxide free radical.
Finally, the hydroperoxide free radical abstracts a hydrogen
free radical from a second molecule of cumene to form cumene hydroperoxide and
a new tertiary free radical.
Cumene hydroperoxide degradation.
The degradation of the cumene hydroperoxide proceeds via a carbocation
mechanism. In the first step, a pair of electrons on the oxygen of the
hydroperoxide's “hydroxyl group” is attracted to a proton of the H3O+
molecule, forming an oxonium ion.
Next, the oxonium ion becomes stabilized when the positively
charged oxygen leaves in a water molecule. This loss of a water molecule
produces a new oxonium ion.
A phenide ion shift to the oxygen atom (which creates a
tertiary carbocation) stabilizes the positively charged oxygen. (A phenide ion
is a phenyl group with an electron bonding pair available to form a new bond to
the ring.)
The carbocation is stabilized by an acid-base reaction with
a water molecule, leading to the formation of an oxonium ion.
The loss of a proton stabilizes the oxonium ion.
Next, a proton is picked up by the ether oxygen in an
acid-base reaction, yielding a new oxonium ion.
The positively charged ether oxygen pulls the electrons in
the oxygen-carbon bond toward itself, thus delocalizing the charge over both of
the atoms. The partial positive charge on the carbon attracts the nonbonding
electron pair from the oxygen of the OH group, allowing the electrons in the
original oxygen-carbon bond to be released back to the more electronegative oxygen
atom.
Finally, a proton is lost from the protonated acetone
molecule, leading to the formation of acetone.
Ethers
Ethers are alkoxy (RO—)-substituted
alkanes, alkenes, and alkynes. As with alcohols, only saturated carbon atoms
may be substituted in alkenes and alkynes.
Ethers are commonly named by listing the names of the groups
attached to the oxygen atom and adding the word ether. Examples include:
IUPAC nomenclature names ethers as alkoxy alkanes, alkoxy
alkenes, or alkoxy alkynes. The group in the chain that has the greatest number
of carbon atoms is designated the parent compound. In the case of aromatic
ethers, the benzene ring is the parent compound.
Cyclic ethers, oxygen-containing ring systems, are normally
called by their common names.
Physical
properties
The bonds between the oxygen atom
and the carbon atoms of the alkyl groups in an ether molecule are polarized due
to a difference in electronegativities between carbon and oxygen. In addition,
the bond angle between the alkyl groups on the oxygen is 110°. These facts show
that ether molecules must be dipoles (molecules having both a center of
positive and negative charge) with weak polarities. Thus, the structure of
ether is similar to that of water.
However, in water the hydrogen atoms
have a greater partial positive charge than the hydrogen atoms on ether. In
water, the charge is localized (only on) the hydrogens and not delocalized
(spread throughout) as with the alkyl groups, so the charge is stronger in
water than in ethers.
Like water, ether is capable of
forming hydrogen bonds. However, because of the delocalized nature of the
positive charge on the ether molecule's hydrogen atoms, the hydrogens cannot
partake in hydrogen bonding. Thus, ethers only form hydrogen bonds to other
molecules that have hydrogen atoms with strong partial positive charges.
Therefore, ether molecules cannot form hydrogen bonds with other ether
molecules. This leads to the high volatility of ethers. Ethers are capable,
however, of forming hydrogen bonds to water, which accounts for the good
solubility of low molecular weight ethers in water.
Table
1 shows boiling points for some simple ethers and
the boiling points of alcohols of the same number of carbon atoms. Notice that
due to the hydrogen bonding between alcohol molecules, all alcohols have
appreciably higher boiling points than their isomeric ethers.
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